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9w^2-76=0
a = 9; b = 0; c = -76;
Δ = b2-4ac
Δ = 02-4·9·(-76)
Δ = 2736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2736}=\sqrt{144*19}=\sqrt{144}*\sqrt{19}=12\sqrt{19}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{19}}{2*9}=\frac{0-12\sqrt{19}}{18} =-\frac{12\sqrt{19}}{18} =-\frac{2\sqrt{19}}{3} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{19}}{2*9}=\frac{0+12\sqrt{19}}{18} =\frac{12\sqrt{19}}{18} =\frac{2\sqrt{19}}{3} $
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